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$openfiledialog1.InitialDirectory = "C:\Download\cert"
$openfiledialog1.Filter = "Config|*.cfg"

if ($openfiledialog1.ShowDialog() -eq 'OK')
{
$SelectedPath = $openfiledialog1.FileName

Ive used several hard coded attempt but when running it opens in the same folder as my exe not where I specify any ideas?

When

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Product, version and build:pSS 2019 current build
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[TOPIC MOVED TO POWERSHELL GUIS FORUM BY MODERATOR]

I ran a quick test and the dialog opens to the correct path when I set the InitialDirectory property.

Does the specified folder exist? If not, it might default to another path.

yes it does but I am displaying it and it looks like this

Microsoft.powershell.core\filesystem:\\The correct path

is the Microsoft.powershell.core\filesystem:\\ causing the issue?

Yes, that will cause the problem. You will have to trim that portion out.

fyi I am getting the path with this code

$A = Get-Location
$global:LocalPath = $A.path.ToString()

to find where my exe is running then + "\subfolder" for the open location

is something wrong with that?

Get-Location will only give you the working directory which isn't necessarily the directory of the executable.

I recommend using the either:

Get-ScriptDirectory function (snippet: getscriptdirectory)
Or if you are using the latest version of PowerShell Studio 2019, the $PSScriptRoot variable.

that worked much better and allowed the open dialog to work as expected.

Much thanks