Menu Button Behavior

[jvierra]

Not enough information. What context menus?

[jvierra]

Yes - within a container the calculations are wrong. We need to calculate the position relative to the group box then translate to the screen.

Here is an example.

[njcappa]

Do I need to open a request/ticket elsewhere for this to be escalated for a fix?

[jvierra]

You can fix it yourself. Just make a new control set with the fixes.

I will post to Alex or Devon to have them look at this thread. Changing it may take some time. We willl have to let them decide. I am not a Sapien employee. THe people in this forum are all just community members.

[njcappa]

Re-creating the control set does not fix it. The issue remains.

Please let them know that.

[jvierra]

No. You have to create a new control set based on the old control set but with updated code. See the documentation on how to create custom control sets to learn how to do this.

Custom control sets are a feature of PSS that let use modify controls or define new control groups with code. The sets in PSS are mostly demos of what can be done or are just conveniences that Sapien has built over the years. They are fully modifiable. I currently have a number that are updates based on the original Sapien control.

This is how I patched the position.

Code: [Select all] [Expand/Collapse] [Download] (Untitled.ps1)

1. $menuButton2_Click={
2.     #Show the menu
3.     $point = New-Object System.Drawing.Point ($groupbox2.Location.X, $groupbox2.Bottom)
4.     $menuButtonContextmenustrip2.Show($form1.PointToScreen($point));
5. }

You can change this to get the parent container on button initialization so that it always uses the containers position as the anchor.

[jvierra]

Here is the generic solution that will work in all versions of the control.

Code: [Select all] [Expand/Collapse] [Download] (Untitled.ps1)

1. $menuButton3_Click={
2.     #Show the menu
3.     $x = $this.Parent.Location.X + $this.Location.X + 10
4.     $y = $this.Parent.Location.Y + $this.Location.Y + 10
5.     $point = New-Object System.Drawing.Point ($x, $y)
6.     $menuButtonContextmenustrip3.Show($this.FindForm().PointToScreen($point));
7. }

[njcappa]

Makes sense - I set the drawing point to the value I needed and it worked just fine.

Thanks

[jvierra]

I had a bit of time to look at the best way to do this. If the control set uses the following line all will be well.

$menuButtonContextmenustrip1.Show($this.Parent.PointToScreen($point))