notifyicon closes the application

[Gordeev Alexaender]

Hi,

If you execute the code below, the program closes.
What could be the problem? that need to be left alone notifyicon. I've tried to change $form.hide() to $form.ShowInTaskbar = $false. All the same, there are no errors.

$form_Resize={
#TODO: Place custom script here
if (Form.WindowState -eq "Minimized")
{
$form.hide()
#$Monitoring.ShowInTaskbar = $false
}
}


$notifyicon1_MouseDoubleClick=[System.Windows.Forms.MouseEventHandler]{
#Event Argument: $_ = [System.Windows.Forms.MouseEventArgs]
#TODO: Place custom script here
$form.WindowState = 'Normal'
#$form.ShowInTaskbar = $true

}

[jvierra]

Yes. That is correct. If you hide a dialog it is the same as closing it.

[Gordeev Alexaender]

How, then, hide the form, remove the icon from the taskbar and leave only the icon in the system tray? and expand by double-clicking on notifyicon back to the form, if necessary.

[jvierra]

You can't with PowerShell. PowerShell uses only modal dialogs. When a dialog is hidden it is closed. When the dialog closes it will remove the notify icon and all events from the system and the script will terminate.
Here is one way to use the icon without a form: https://technet.microsoft.com/en-us/lib ... 30952.aspx

[DevinL]

Duplicate topic, conversation continues here: viewtopic.php?f=21&t=10661